Question

1. titanium has five common isotopes with the 8.0% ti - 46, 7.8% ti - 47, 73.4% ti - 48, 5.5% ti - 49, and 5.3% ti - 50. what is the average atomic mass of titanium?

Explanation:

Step1: Recall the formula for average atomic mass

The formula is $\sum_{i = 1}^{n}(m_i\times p_i)$, where $m_i$ is the mass of the isotope and $p_i$ is the percentage abundance (in decimal form) of the isotope.

Step2: Convert percentages to decimals

$8.0\%=0.08$, $7.8\% = 0.078$, $73.4\%=0.734$, $5.5\%=0.055$, $5.3\% = 0.053$.

Step3: Multiply mass - abundance for each isotope

For Ti - 46: $46\times0.08 = 3.68$.
For Ti - 47: $47\times0.078=3.666$.
For Ti - 48: $48\times0.734 = 35.232$.
For Ti - 49: $49\times0.055 = 2.695$.
For Ti - 50: $50\times0.053=2.65$.

Step4: Sum up the products

$3.68 + 3.666+35.232 + 2.695+2.65=47.923$.

Answer:

$47.923$