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Question
titanium is used in specialized engineering applications because it is strong and \light\. actually, it isnt particularly light at the atomic level, however, it is less dense than iron (7.87 g/cm3) by a factor of 1.75. there are many factors that contribute to density, including the way the atoms pack together, the radius of the atoms etc. we can easily show that the reason for the difference in density in this case is not just the weight of the atoms since the ratio of the average atomic weights of iron and titanium is not exactly 1.75. what is the ratio of the average atomic weight of these two metals? ratio iron / titanium = 1.47 ratio iron / titanium = 1.37 ratio iron / titanium= 1.27 ratio iron / titanium = 1.17 dont test me yet, i am trying to gain an understanding before attempting to answer this question.
Step1: Identify atomic weights
The atomic weight of iron (Fe) is 55.845 and of titanium (Ti) is 47.88.
Step2: Calculate the ratio
The ratio of the average atomic - weight of iron to that of titanium is $\frac{55.845}{47.88}\approx1.17$.
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1.17