Question

k/u - true or false question 11 (1 point) if $l = 2$, then we are referring to a \d\ orbital. true false question 12 (1 point) the following is a possible set of quantum numbers for an element in the $3^{rd}$ period. $n = 3, l = 1, m_l=-2, m_s = +\frac{1}{2}$ true false

Explanation:

Step1: Recall orbital - angular - momentum quantum number rules

The orbital - angular - momentum quantum number \(l\) determines the shape of the orbital. When \(l = 0\), it's an \(s\) - orbital; when \(l=1\), it's a \(p\) - orbital; when \(l = 2\), it's a \(d\) - orbital; when \(l=3\), it's an \(f\) - orbital. So for \(l = 2\), we have a \(d\) - orbital.

Step2: Recall magnetic - quantum - number rules

The magnetic quantum number \(m_l\) has values ranging from \(-l\) to \(l\). Given \(n = 3\) (the principal quantum number), \(l = 1\) (a \(p\) - orbital). For \(l = 1\), \(m_l\) can take values \(-1,0,1\). Since \(m_l=-2\) when \(l = 1\) is not allowed.

Answer:

Question 11: True
Question 12: False