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unit 1 hw: atomic structure & properties
part i: short response
use the pes spectrum below to answer questions 1–4.
pes spectrum with binding energy (mj/mol) and relative number of electrons, peaks at 104, 6.84, 4.98, 2.29, 1.76
- what element does this spectrum represent? _______________
- which peak represents the 2s subshell? place an ‘x’ above this peak on the pes.
- an electron from which peak (104, 6.84, 4.98, 2.29, 1.76 mj/mol) would have the greatest velocity after ejection? why?
- how many valence electrons does this atom have?
- why does an anion of p³⁻ have a larger radius than a neutral atom of p?
section 2 is mcq on college bo...
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- Phosphorus (P)
- (Place 'x' above the peak with binding energy 6.84 MJ/mol)
- 1.76 MJ/mol; because it has the lowest binding energy, so the ejected electron has the most kinetic energy (and thus greatest velocity) by \( KE = h
u - BE \)
- 5
- \( \text{P}^{3-} \) has gained 3 electrons, increasing electron - electron repulsions in the same energy levels, causing the electron cloud to expand, and there is no increase in nuclear charge to pull electrons closer, so the radius is larger.