Question

use the activity series below to predict the products of each of the following reactions. do not worry about balancing the equations.
li > k > ba > sr > ca > na > mg > al > mn > zn > cr > fe > cd > co > ni > sn > pb > h > sb > bi > cu > ag > pd > hg > pt > au
zn₃(po₄)₂ + ca → ?
no reaction
znca + po₄
ca₃(po₄)₂ + zn

Explanation:

Step1: Check activity series

In the activity series, Ca (Calcium) is more reactive than Zn (Zinc) because Ca is to the left of Zn in the given series (Li > K > Ba > Sr > Ca > Na > Mg > Al > Mn > Zn...).

Step2: Predict reaction type

This is a single - displacement reaction. In a single - displacement reaction, a more reactive metal displaces a less reactive metal from its compound. Since Ca is more reactive than Zn, Ca will displace Zn from $Zn_3(PO_4)_2$.
The reaction will be: $Zn_3(PO_4)_2+3Ca
ightarrow Ca_3(PO_4)_2 + 3Zn$ (we are not worrying about balancing here as per the question, but the products are $Ca_3(PO_4)_2$ and Zn).

Answer:

C. $Ca_3(PO_4)_2 + Zn$