QUESTION IMAGE
Question
use the data in the table to answer the following questions. how many grams of compound were formed?
aluminum and liquid bromine reaction
| before reaction | after reaction | |
|---|---|---|
| liquid bromine | 100.0 g | 8.5 g |
| compound | 0.0 g |
100.0 g
101.8 g
10.3 g
91.5 g
Step1: Calculate used liquid bromine mass
Mass of used liquid bromine = Initial mass - Remaining mass = $100.0 - 8.5=91.5$ g
Step2: Apply law of conservation of mass
According to the law of conservation of mass, mass of compound formed = Mass of aluminum used+Mass of used liquid bromine. Mass of aluminum used is 10.3 g and mass of used liquid bromine is 91.5 g. So mass of compound formed = $10.3 + 91.5=101.8$ g
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101.8 g