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use the periodic table to answer the question. which statement correctl…

Question

use the periodic table to answer the question. which statement correctly compares the valence electrons for atoms of francium (fr) and barium (ba)? (1 point) barium has more valence electrons, and they are in a higher energy level. barium has fewer valence electrons, but they are in a higher energy level. francium has more valence electrons, and they are in a higher energy level. francium has fewer valence electrons, but they are in a higher energy level.

Explanation:

Answer:

To solve this, we analyze the periodic table positions:

  • Francium (Fr) is in Group 1 (IA), so it has 1 valence electron.
  • Barium (Ba) is in Group 2 (IIA), so it has 2 valence electrons.
  • Both are in Period 7, so their valence electrons are in the same energy level (n = 7). Wait, no—wait, Fr is Period 7, Ba is Period 6? Wait, no, looking at the table: Fr is in Period 7, Ba is in Period 6? Wait, no, the table shows Fr (atomic number 87) in Period 7, Ba (atomic number 56) in Period 6. Wait, no, the periodic table: Periods are rows. Row 1: H, He; Row 2: Li, Be...; Row 3: Na, Mg...; Row 4: K, Ca...; Row 5: Rb, Sr...; Row 6: Cs, Ba...; Row 7: Fr, Ra... Ah, right! So Fr is Period 7, Ba is Period 6. Wait, no—Cs (55) and Ba (56) are Period 6, Fr (87) and Ra (88) are Period 7. So:
  • Fr (Group 1, Period 7): valence electrons = 1, energy level (n) = 7.
  • Ba (Group 2, Period 6): valence electrons = 2, energy level (n) = 6.

Wait, no—energy level (n) is the period number. So Ba is Period 6 (n=6), Fr is Period 7 (n=7). So Fr’s valence electrons are in a higher energy level (n=7) than Ba’s (n=6). But Fr has 1 valence electron, Ba has 2. So:

  • Francium has fewer valence electrons (1 vs. 2) than Barium, but its valence electrons are in a higher energy level (Period 7 vs. Period 6).

So the correct option is: Francium has fewer valence electrons, but they are in a higher energy level.

(Note: The original options might have a typo, but based on the periodic table, Fr is Period 7, Ba is Period 6. So Fr’s valence electrons are in a higher energy level (n=7) than Ba’s (n=6). Fr has 1 valence electron, Ba has 2. So the last option: "Francium has fewer valence electrons, but they are in a higher energy level." is correct.)

(If we consider the options as given, the last option is: "Francium has fewer valence electrons, but they are in a higher energy level." So that’s the answer.)