Question

1. using gay-lussacs law, calculate the new temperature in the following situation: a sample of gas has a pressure of 3.60 atm and a temperature of 22 °c. if the pressure decreases to 1.75 atm, what will be its celsius temperature if the volume remains constant? round to the nearest whole place

______ °c

1. using gay-lussacs law, calculate the new pressure in the following situation: a tank of acetylene sits on the back of a truck. during the afternoon, the temperature of the gas has reached 38 °c (311 k) with a pressure of 505 kpa. one night, the temperature drops to 0 °c (273 k). since the gas was in a metal tank, the volume remained constant. what is the new pressure? your answer should be a whole number

______ kpa

Explanation:

Step1: List Gay-Lussac's Law

$\frac{P_1}{T_1} = \frac{P_2}{T_2}$

Step2: Convert temp to Kelvin

$T_1 = 22^\circ\text{C} + 273.15 = 295.15\ \text{K}$

Step3: Rearrange for $T_2$

$T_2 = \frac{P_2 T_1}{P_1}$

Step4: Substitute values for Q5

$T_2 = \frac{1.75\ \text{atm} \times 295.15\ \text{K}}{3.60\ \text{atm}} \approx 144.7\ \text{K}$

Step5: Convert back to Celsius

$T_2 = 144.7 - 273.15 \approx -128^\circ\text{C}$

Step6: Substitute values for Q6

$T_2 = 0^\circ\text{C} + 273.15 = 273.15\ \text{K}$
$P_2 = \frac{P_1 T_2}{T_1} = \frac{505\ \text{kPa} \times 273.15\ \text{K}}{311\ \text{K}} \approx 443\ \text{kPa}$

Answer:

1. $\boldsymbol{-128^\circ\text{C}}$
2. $\boldsymbol{443\ \text{kPa}}$