Question

using the periodic table, find the molar mass of silver nitrate (agno₃). write your answer to the hundredths place. round if necessary.

Explanation:

Step1: Identify molar - masses of elements

From the periodic table, the molar mass of Ag (silver) is approximately 107.87 g/mol, N (nitrogen) is approximately 14.01 g/mol, and O (oxygen) is approximately 16.00 g/mol.

Step2: Calculate molar mass of AgNO₃

The formula for silver nitrate is AgNO₃. There is 1 Ag, 1 N, and 3 O atoms.
The molar mass $M$ of AgNO₃ is $M = 1\times107.87+1\times14.01 + 3\times16.00$.
$M=107.87 + 14.01+48.00$.
$M = 169.88$ g/mol.

Answer:

169.88 g/mol