Question

3 viable lewis dot structures are shown for dinitrogen oxide, n2o. assess their formal charges and state which structure is most valid. what was your reasoning? explain.
a)
b) how many sigma and pi bonds are in structure a?
c) how many sigma and pi bonds are in structure b?

Explanation:

Step1: Recall Lewis - structure rules

Check formal charges and octet - rule compliance for each structure.

Step2: Calculate formal charges

For structure A:
Formal charge on N (left) = 5 - 4 - 2 = - 1
Formal charge on N (right) = 5 - 4 - 2 = - 1
Formal charge on O = 6 - 4 - 2 = 0
For structure B:
Formal charge on N (left) = 5 - 3 - 2 = 0
Formal charge on N (right) = 5 - 4 - 1 = 0
Formal charge on O = 6 - 2 - 4 = 0
For structure C:
Formal charge on N (left) = 5 - 2 - 3 = 0
Formal charge on N (right) = 5 - 5 - 0 = 0
Formal charge on O = 6 - 6 - 1=-1

Step3: Determine the most valid structure

Structure B has all atoms with formal charges closest to zero and satisfies the octet - rule for all atoms.

Step4: Count sigma and pi bonds

In a double - bond, there is 1 sigma and 1 pi bond. In a single - bond, there is 1 sigma bond.
For structure B:
There are 3 sigma bonds and 2 pi bonds.
For structure C:
There are 3 sigma bonds and 2 pi bonds.

Answer:

a) Structure B is the most valid because it has formal charges closest to zero for all atoms and satisfies the octet - rule for all atoms.
b) 3 sigma and 2 pi bonds in structure B.
c) 3 sigma and 2 pi bonds in structure C.