Question

what is the electron configuration for tin (sn), with an atomic number of 50? 1s²2s²2p⁶3s²3p⁶4s²3d¹ 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p² 1s²2s²2p⁶3s²3p⁶4s²4d¹ 1s²2s²2p⁶3s²3p⁶4s²4d¹⁰4p⁶5s²5d¹⁰5p²

Explanation:

Step1: Recall electron - filling order

Electrons fill orbitals in the order 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, etc. The s - orbital can hold 2 electrons, p - orbital can hold 6 electrons, d - orbital can hold 10 electrons.

Step2: Fill electrons for tin (Sn) with atomic number 50

Starting with 1s, we fill electrons until we reach 50 electrons.
1s²: 2 electrons; 2s²: 2 electrons; 2p⁶: 6 electrons; 3s²: 2 electrons; 3p⁶: 6 electrons; 4s²: 2 electrons; 3d¹⁰: 10 electrons; 4p⁶: 6 electrons; 5s²: 2 electrons; 4d¹⁰: 10 electrons; 5p²: 2 electrons.
The sum of electrons is \(2 + 2+6 + 2+6 + 2+10 + 6+2 + 10+2=50\).

Answer:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p²