Question

what is the empirical formula of a compound that was calculated from the % mass and grams to have the following moles: 0.136 mol c, 0.175 mol h, 0.035 mol o input the subscript values in c h o order according to the format.
format: input on the subscripts in order as a single number starting from left to right for each element including a 1 value as appropriate. for example, for a formula of c₂h₃o₂br₁ or c₂h₃o₂br the input is 2321

Explanation:

Step1: Divide by smallest mole value

We divide the moles of each element by the smallest number of moles among them. The smallest number of moles is 0.035 mol (for O).
For C: $\frac{0.136}{0.035}\approx 3.89$
For H: $\frac{0.175}{0.035}= 5$
For O: $\frac{0.035}{0.035}=1$

Step2: Round to whole - numbers

The value for C, 3.89, is close to 4.

Answer:

451