Question

what is the formula for the ionic compound of sodium and bromine? na is in group 1 and br is in group 7a or 17. nabr₂ nabr nabr₃ na₃br

Explanation:

Step1: Determine the ions' charges

Sodium (Na) in group 1 loses 1 electron to form $Na^+$ (charge +1). Bromine (Br) in group 17 gains 1 electron to form $Br^-$ (charge - 1).

Step2: Balance the charges

To form a neutral ionic - compound, the charges must balance. Since the charges of $Na^+$ and $Br^-$ are equal in magnitude but opposite in sign, the ratio of sodium to bromine is 1:1.

Answer:

B. NaBr