Question

what is the molarity of a solution in which 5.6 moles of sodium nitrate is dissolved in water to a final volume of 4.9 l? ? (mol/l)

Explanation:

Step1: Recall molarity formula

Molarity $M = \frac{\text{moles of solute}}{\text{volume of solution (L)}}$

Step2: Substitute given values

$M = \frac{5.6\ \text{mol}}{4.9\ \text{L}}$

Step3: Calculate the result

$M = 1.1428... \approx 1.1\ \text{mol/L}$ (rounded to two significant figures)

Answer:

$1.1\ \frac{\text{mol}}{\text{L}}$