Question

what is the molecular geometry of h₂s? lewis structure: h—s—h with two lone pairs on s options: tetrahedral, linear, bent, trigonal planar

Explanation:

Step1: Determine the Lewis structure and electron - domain geometry

For \(H_2S\), the central atom is \(S\). The valence electrons of \(S\) is \(6\), and each \(H\) contributes \(1\) valence electron, so the total number of valence electrons is \(6 + 2\times1=8\). In the Lewis structure, \(S\) forms single bonds with two \(H\) atoms, and there are two lone pairs of electrons on the \(S\) atom. The electron - domain geometry (considering both bonding and non - bonding electron pairs) around the central \(S\) atom is tetrahedral because the number of electron domains (2 bonding domains from \(S - H\) bonds and 2 non - bonding domains from lone pairs) is \(4\).

Step2: Determine the molecular geometry

The molecular geometry is determined by the arrangement of the bonding electron pairs (the atoms) around the central atom, taking into account the lone pairs. The formula for determining molecular geometry from electron - domain geometry: when the electron - domain geometry is tetrahedral and there are 2 lone pairs and 2 bonding pairs, the molecular geometry is bent. This is because the lone pairs of electrons repel the bonding pairs, causing the \(H - S - H\) bond angle to be less than the ideal tetrahedral angle (around \(109.5^{\circ}\)) and the overall shape of the molecule (the arrangement of the \(H\) atoms around \(S\)) to be bent.

Answer:

The molecular geometry of \(H_2S\) is bent. So the correct option is the one labeled "bent".