Question

1. what would be the new volume if 250 cm³ of gas at 25°c and 730 mm pressure were changed to standard conditions of temperature and pressure? (n = constant)

	p	t	v	n
final				--
effect	↑	↓		--

Explanation:

Step1: Identify standard - conditions values

Standard - temperature $T_2=273\ K$ and standard - pressure $P_2 = 760\ mm\ Hg$. Initial pressure $P_1 = 730\ mm\ Hg$, initial temperature $T_1=25 + 273=298\ K$, initial volume $V_1 = 250\ cm^3$.

Step2: Use the combined gas law formula

The combined gas law is $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$. We need to solve for $V_2$. Rearranging the formula gives $V_2=\frac{P_1V_1T_2}{T_1P_2}$.

Step3: Substitute the values

Substitute $P_1 = 730$, $V_1 = 250$, $T_1 = 298$, $P_2 = 760$, and $T_2 = 273$ into the formula:
\[

$$\begin{align*} V_2&=\frac{730\times250\times273}{298\times760}\\ &=\frac{730\times250\times273}{226480}\\ &=\frac{730\times68250}{226480}\\ &=\frac{49822500}{226480}\\ &\approx220\ cm^3 \end{align*}$$

\]

Answer:

$220\ cm^3$