Question

what is the oxidation number for s in the compound so₃? (recall that o has an oxidation number of −2.) 0 +2 +4 +6

Explanation:

Step1: Let the oxidation number of S be \( x \).

In a neutral compound, the sum of oxidation numbers is 0. For \( SO_3 \), there is 1 S atom and 3 O atoms. The oxidation number of O is -2.

Step2: Set up the equation.

The sum of oxidation numbers: \( x + 3\times(-2)=0 \)

Step3: Solve the equation.

\( x - 6 = 0 \), so \( x = +6 \).

Answer:

+6