Question

what is the pressure of 4 moles of helium in a 50 l tank at 308 k? use pv = nrt.
a. 0.13 atm
b. 0.51 atm
c. 24.64 atm
d. 2.02 atm

Explanation:

Step1: Identify the known values

$n = 4\ mol$, $V=50\ L$, $T = 308\ K$, $R=0.0821\ L\cdot atm/(mol\cdot K)$

Step2: Rearrange the ideal - gas law formula

$P=\frac{nRT}{V}$

Step3: Substitute the values into the formula

$P=\frac{4\ mol\times0.0821\ L\cdot atm/(mol\cdot K)\times308\ K}{50\ L}$
$P=\frac{4\times0.0821\times308}{50}atm$
$P=\frac{100.9952}{50}atm$
$P = 2.019904\ atm\approx2.02\ atm$

Answer:

D. 2.02 atm