Question

what product is formed when the compound below is oxidized with k₂cr₂o₇?
ch₃
ch₃chch—c—h
br
ch₃
ch₃chc=choh
br
ch₃ o
ch₃chch—c—oh
br
ch₃
ch₃chchch₂oh
br
no reaction occurs.

Explanation:

Step1: Identify the functional - group

The given compound has an aldehyde functional - group ($-CHO$). Potassium dichromate ($K_2Cr_2O_7$) is a strong oxidizing agent.

Step2: Recall the oxidation of aldehydes

Aldehydes are oxidized to carboxylic acids by strong oxidizing agents like $K_2Cr_2O_7$ in acidic medium. The general reaction is $R - CHO+[O]
ightarrow R - COOH$.

Step3: Determine the product

The given aldehyde will be oxidized to a carboxylic acid. The structure of the product will have the $-CHO$ group converted to $-COOH$ group while the rest of the carbon - chain remains the same.

Answer:

The second option: $\mathrm{CH_3CH(CH_3)CH(Br)COOH}$