Question

what products are formed when the acetal below is hydrolyzed with water and sulfuric acid? och₃ h - c - ch₂ch₂ch₂ch₃ och₃ o + 2 ch₃oh h - c - ch₂ch₂ch₂ch₃ o + 2 ch₃ch₂ch₂ch₂oh h - c - ch₃ hoch₂ch₂ch₂ch₂ch₃ + 2 ch₃oh o + 2 ch₃ch₂oh h - c - ch₂ch₂ch₂ch₃ och₃ h - c - ch₂ch₂ch₃ och₃

Explanation:

Step1: Recall acetal hydrolysis

Acetal hydrolysis in acidic medium (water - sulfuric acid) breaks the C - O bonds of the acetal group. The general reaction of an acetal $R_2C(OR')_2$ with water in acidic conditions gives a carbonyl compound (aldehyde or ketone) and the corresponding alcohol.

Step2: Identify the acetal structure

The given acetal has the structure $H - C(CH_2CH_2CH_2CH_3)(OCH_3)_2$. When hydrolyzed, the two $-OCH_3$ groups will be replaced by an oxygen double - bonded to the central carbon.

Step3: Determine the products

The products of the hydrolysis of the given acetal are an aldehyde $H - C(=O)-CH_2CH_2CH_2CH_3$ (pentanal) and two moles of methanol ($CH_3OH$).

Answer:

The first option: $\ce{H - C(=O)-CH_2CH_2CH_2CH_3 + 2CH_3OH}$