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when producing hydrogen iodide, the energy of the reactants is 581 kj/m…

Question

when producing hydrogen iodide, the energy of the reactants is 581 kj/mol, and the energy of the products is 590 kj/mol. the equation is shown. h₂ + i₂ → 2hi what is the total energy of the reaction? is this an endothermic or exothermic reaction? (1 point) -9 kj/mol, endothermic -9 kj/mol, exothermic 9 kj/mol, endothermic 9 kj/mol, exothermic

Explanation:

Step1: Calculate energy change

The energy change ($\Delta H$) of a reaction is calculated as the energy of products minus the energy of reactants. $\Delta H=E_{products}-E_{reactants}$. Given $E_{reactants} = 581\ kJ/mol$ and $E_{products}=590\ kJ/mol$, so $\Delta H = 590 - 581=9\ kJ/mol$.

Step2: Determine reaction type

If $\Delta H> 0$, the reaction is endothermic as it absorbs energy from the surroundings. Since $\Delta H = 9\ kJ/mol>0$, this is an endothermic reaction.

Answer:

C. 9 kJ/mol, endothermic