Question

which is the electronic configuration for oxygen? ○ $1s^2 2s^2 2p^1$ ○ $1s^2 2s^2 2p^3$ ○ $1s^2 2s^2 2p^4$ ○ $1s^2 2s^2 2p^6$

Explanation:

Oxygen has an atomic number of 8, meaning it has 8 electrons. The electron configuration follows the Aufbau principle. The 1s orbital holds 2 electrons, 2s holds 2, and the 2p orbital will hold the remaining electrons. After filling 1s² and 2s² (total 4 electrons), we have 4 left for the 2p orbital, so the configuration is \(1s^2 2s^2 2p^4\).

Answer:

\(1s^2 2s^2 2p^4\) (the third option: \(1s^2 2s^2 2p^4\))