Question

1. which equation best represents the conservation of matter? (1 point)

choice a 6h2o+10co2→c6h12o6+4o2
choice b 3h2o+3co2→c6h12o6+3o2
choice c 3h2o+3co2→c6h12o6+9o2
choice d 6h2o+6co2→c6h12o6+6o2

Explanation:

Step1: Check atom - count on both sides

For conservation of matter, atom numbers on reactant and product sides must match. In option D, for carbon: 6 on reactant side ($6$ in $6CO_2$) and 6 in $C_6H_{12}O_6$ on product side. For hydrogen: $6\times2 = 12$ in $6H_2O$ on reactant side and 12 in $C_6H_{12}O_6$ on product side. For oxygen: $(6 + 12)$ in $6H_2O+6CO_2$ and $(6 + 12)$ in $C_6H_{12}O_6 + 6O_2$.

Answer:

D. $6H_2O+6CO_2
ightarrow C_6H_{12}O_6+6O_2$