Question

which of the following arranges the bonds in order of decreasing bond length? choose 1 answer: a c≡o > c=s > c=o b c=o > c=s > c≡o c c=s > c=o > c≡o d c≡o > c=o > c=s

Explanation:

Step1: Recall bond - length rule

Bond length decreases with increasing bond order. Triple - bonds are shorter than double - bonds. Also, for the same bond order, the bond length increases with the increasing atomic radius of the atoms involved.

Step2: Analyze the bonds

The $C\equiv O$ is a triple - bond, and $C = O$ and $C = S$ are double - bonds. Since the atomic radius of $S$ is larger than that of $O$, the $C = S$ bond is longer than the $C = O$ bond. The triple - bond $C\equiv O$ is the shortest among them. So, the order of decreasing bond length is $C = S>C = O>C\equiv O$.

Answer:

C. $C = S>C = O>C\equiv O$