Question

which of the following is most likely to be the correct formula for calcium bromide? a cabr b ca₂br c kbr d kbr₂ e cabr question 5

Explanation:

Step1: Determine calcium's charge

Calcium (Ca) is in group 2 of the periodic - table and has a +2 charge ($Ca^{2 +}$).

Step2: Determine bromine's charge

Bromine (Br) is in group 17 of the periodic - table and has a - 1 charge ($Br^{-}$).

Step3: Balance charges

To balance the charges in an ionic compound, we need 2 bromide ions for every calcium ion. So the formula is $CaBr_{2}$. But among the given options, we need to analyze them based on correct ion - combinations. Options C and D have potassium (K) which is incorrect as we are looking for calcium bromide. Options A, B, and E have incorrect combinations. The correct formula for calcium bromide should have one calcium and two bromines. Since the options are likely mis - typed and assuming the intention, we know the correct combination is based on the charges. Calcium with a +2 charge and bromine with a - 1 charge gives $CaBr_{2}$, but if we consider the closest correct ion - based option among the given ones, we note that calcium and bromine are the correct elements we need.

Answer:

There is no correct option given as the correct formula for calcium bromide is $CaBr_{2}$, but if we assume it's a matter of correct elements combination, the closest in terms of elements is an option with Ca and Br. However, strictly speaking, none of the provided options ($A. CaBr$, $B. Ca_{2}Br$, $C. KBr$, $D. KBr_{2}$, $E. CaBr$) is correct.