Question

which one of the following is the correct dissociation equation for albr₃? answer: a albr₃(s) → 3 al⁺(aq) + br⁻(aq) b 2 albr₃(s) → 2 al³⁺(aq) + 3 br₂⁻(aq) c albr₃(s) → al³⁺(aq) + 3 br⁻(aq) d albr₃(s) → al⁺(aq) + 3 br⁻(aq)

Explanation:

Step1: Recall aluminum ion and bromide ion charges

Aluminum (Al) forms a $Al^{3 +}$ ion and bromine (Br) forms a $Br^{-}$ ion.

Step2: Write dissociation equation

When $AlBr_{3}$ dissociates in aqueous solution, it breaks into one $Al^{3+}$ ion and three $Br^{-}$ ions. The correct dissociation equation is $AlBr_{3}(s)
ightarrow Al^{3 +}(aq)+3Br^{-}(aq)$.

Answer:

C. $AlBr_{3}(s)
ightarrow Al^{3 +}(aq)+3Br^{-}(aq)$