Question

which set of numbers gives the correct possible values of l for n = 2?
0
0, 1
0, 1, 2
0, 1, 2, 3

Explanation:

Step1: Recall quantum number rule

For a given principal quantum number $n$, the angular - momentum quantum number $l$ can take values from $0$ to $n - 1$.

Step2: Calculate possible values of $l$ for $n = 2$

When $n=2$, $l$ can be $l = 0$ and $l = 1$ since $l$ ranges from $0$ to $n - 1=2 - 1 = 1$.

Answer:

0, 1