Question

write the complete electron configuration for each of the following: part a nitrogen express your answer in complete form, in order of increasing energy. for example, he2s^22p^2 would be entered as 1s^22s^22p^2. part b sulfur express your answer in complete form, in order of increasing energy. for example, he2s^22p^2 would be entered as 1s^22s^22p^2.

Explanation:

Step1: Recall nitrogen's atomic number

Nitrogen has atomic number 7. Electrons are filled in order of increasing energy levels and sub - levels (1s < 2s < 2p).

Step2: Fill electrons

1s can hold 2 electrons, 2s can hold 2 electrons, and then the remaining 3 electrons go into 2p. So the electron configuration is $1s^{2}2s^{2}2p^{3}$.

Step3: Recall sulfur's atomic number

Sulfur has atomic number 16.

Step4: Fill electrons for sulfur

1s is filled with 2 electrons, 2s with 2 electrons, 2p with 6 electrons, 3s with 2 electrons, and the remaining 4 electrons go into 3p. So the electron configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}$.

Answer:

Part A: 1s^22s^22p^3
Part B: 1s^22s^22p^63s^23p^4