Question

write the formula for these ionic compounds:
iron (ii) chloride
calcium oxide
sodium sulfide
aluminum nitride
magnesium oxide
potassium fluoride

Explanation:

Step1: Identify ion charges

Iron(II): $\text{Fe}^{2+}$, Chloride: $\text{Cl}^-$; Calcium: $\text{Ca}^{2+}$, Oxide: $\text{O}^{2-}$; Sodium: $\text{Na}^+$, Sulfide: $\text{S}^{2-}$; Aluminum: $\text{Al}^{3+}$, Nitride: $\text{N}^{3-}$; Magnesium: $\text{Mg}^{2+}$, Oxide: $\text{O}^{2-}$; Potassium: $\text{K}^+$, Fluoride: $\text{F}^-$

Step2: Balance charge for neutrality

For each compound, adjust ion counts so total positive = total negative charge.

Step3: Write final formulas

Simplify ion ratios to lowest whole numbers.

Answer:

1. Iron (II) Chloride: $\text{FeCl}_2$
2. Calcium Oxide: $\text{CaO}$
3. Sodium Sulfide: $\text{Na}_2\text{S}$
4. Aluminum Nitride: $\text{AlN}$
5. Magnesium Oxide: $\text{MgO}$
6. Potassium Fluoride: $\text{KF}$