Question

write the systematic name of each organic molecule:
structure
cl—c(cl)=ch—ch(ch₃)—ch₃

Explanation:

Step1: Identify the parent chain

The parent chain is the longest carbon chain containing the double bond. Here, the longest chain with the double bond has 5 carbons (pentene).

Step2: Number the parent chain

Number the chain to give the double bond the lowest possible number. The double bond is between carbon 2 and 3 (since we number from the end closest to the double bond and the substituents). Wait, let's re - number: Let's start numbering from the left. The carbons are: C1 (with two Cl), C2 (double bonded to C3), C3 (CH), C4 (CH₃), C5 (CH₃)? Wait, no, let's draw the structure:

C1: bonded to two Cl and C2 (double bond)
C2: double bonded to C1 and single bonded to C3
C3: single bonded to C2, C4, and has a CH₃? Wait, no, the structure is Cl - C(Cl)=CH - CH(CH₃)-CH₃. So the parent chain is 5 carbons (pentene). Numbering from the left (to give the double bond the lowest number, and also consider substituents). The double bond is at position 2 (between C2 and C3).

Step3: Identify substituents

• At C1: two Cl atoms (dichloro)
• At C4: a methyl group (CH₃)

Step4: Combine the names

The parent chain is pent - 2 - ene (since the double bond is at C2). The substituents: at C1, dichloro; at C4, methyl. So the name is 1,1 - dichloro - 4 - methylpent - 2 - ene. Wait, let's check the numbering again. Let's number the carbon chain as follows:

Carbon 1: C with two Cl (Cl - C(Cl)=)
Carbon 2: C = CH -
Carbon 3: CH -
Carbon 4: CH(CH₃)-
Carbon 5: CH₃

So the double bond is between C2 and C3 (so pent - 2 - ene). Substituents: C1 has two Cl (1,1 - dichloro), C4 has a methyl (4 - methyl). So the systematic name is 1,1 - dichloro - 4 - methylpent - 2 - ene.

Answer:

1,1 - dichloro - 4 - methylpent - 2 - ene