Question

1. an ion has 22 protons, 26 neutrons, and 19 electrons. the symbol for the ion is ________. a) 17o2- b) 19f+ c) 19f- d) 17ne2- e) 17o2+

Explanation:

Step1: Determine the element

The number of protons determines the element. With 22 protons, the element is titanium (Ti). But we can also analyze from the given options based on proton - electron relationship.

Step2: Calculate the charge of the ion

The charge of an ion is calculated as the number of protons minus the number of electrons. Given 22 protons and 19 electrons, the charge is \(22 - 19=3+\). However, let's analyze the options one - by - one based on the proton and electron numbers in them.
For option A: Oxygen has 8 protons, not 17, so it's wrong.
For option B: Fluorine has 9 protons. Here, if there are 19 protons, it's wrong. Also, the charge calculation for the given number of protons and electrons in the problem doesn't match this option.
For option C: Fluorine has 9 protons, not 19, so it's wrong.
For option D: Neon has 10 protons, not 17, so it's wrong.
For option E: Oxygen has 8 protons, not 17, so it's wrong. But if we calculate the charge of an ion with 22 protons and 19 electrons correctly, the ion should be \(Ti^{3 +}\), and there is an error in the given options. Assuming we consider the charge - calculation conceptually from the options:
The number of protons gives the atomic number. If we consider the charge calculation based on the general idea of proton - electron difference. The ion has a net positive charge since the number of protons (22) is greater than the number of electrons (19). The charge is \(+ 3\). But among the options, if we calculate the charges for the given proton - electron combinations in the options:
For an ion with 17 protons and 19 electrons, the charge is \(17-19=- 2\) (for options with 17 protons). For an ion with 19 protons and 18 electrons (assuming \(19F^{+}\)), the charge is \(19 - 18 = + 1\).
If we assume there is a mis - typing in the problem and we focus on the charge calculation concept from the options, an ion with 17 protons (oxygen - like number in the wrong context here) and 15 electrons would have a charge of \(17-15 = + 2\). But this is also not in line with the correct element based on 22 protons. If we go by the closest charge - calculation from the options, for an ion with 17 protons and 15 electrons, the symbol would be \(17O^{2+}\) which is option E in a wrong - context way as oxygen has 8 protons in reality. But based on the charge calculation among the given options:
The ion has 22 protons and 19 electrons, so the charge is \(22-19 = 3+\). But if we assume we work with the options' format, an ion with 17 protons and 15 electrons has a \(+ 2\) charge.

Answer:

E. 17O2+ (Note: There is likely an error in the problem as the correct element with 22 protons is titanium and the correct ion should be \(Ti^{3+}\), but among the given options, based on charge - calculation concept, this is the closest in terms of charge representation in the wrong - context of element number)