Question

1. what element does this orbital diagram represent? na n ni 7. how many lone pairs of electrons are there in the lewis dot structure of h2o? 2 4 6 8. what element in correct for the following electron configuration statement; 1s2, 2s2, 2p6, 3s2, 3p4 al p s

Explanation:

14.

Count the electrons in the orbital diagram. Sodium (Na) has 11 electrons, nitrogen (N) has 7 electrons and nickel (Ni) has 28 electrons. Without seeing the actual number of electrons in the diagram precisely, we assume a proper count. If the diagram shows 7 electrons which is characteristic of nitrogen's electron - filling pattern in orbitals.

Draw the Lewis - dot structure of water ($H_2O$). Oxygen is the central atom. Oxygen has 6 valence electrons. It forms 2 single bonds with 2 hydrogen atoms. So, the number of lone pairs on oxygen is 2.

Add up the electrons from the electron - configuration $1s^22s^22p^63s^23p^4$. The sum is $2 + 2+6 + 2+4=16$. Sulfur (S) has 16 electrons.

Answer:

N

7.