Question

1. if reaction #3 occurs, you calculated 0.03885 moles $ce{na_{2}o}$ would be produced from the decomposition of the $ce{nahco_{3}}$ (baking soda). calculate how many grams of $ce{na_{2}o}$ would be produced if reaction #3 occurs.

i need a hint
$\boldsymbol{square}$ g $ce{na_{2}o}$
the answer to this question depends on your answers to previous questions.
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Explanation:

Step1: Find molar mass of $\text{Na}_2\text{O}$

Molar mass of $\text{Na}_2\text{O} = (2\times22.99) + 16.00 = 61.98\ \text{g/mol}$

Step2: Convert moles to grams

$\text{Mass} = \text{Moles} \times \text{Molar Mass}$
$\text{Mass} = 0.03885\ \text{mol} \times 61.98\ \text{g/mol}$

Answer:

$2.408\ \text{g}\ \text{Na}_2\text{O}$