Question

1. 5.00 l of a gas contains 0.965 mol. if the amount of gas is increased to 1.80 mol, what new volume will result (at an unchanged temperature and pressure)?

Explanation:

Step1: Identify the gas - law relationship

At constant temperature and pressure, the volume of a gas is directly proportional to the number of moles (Avogadro's law: $\frac{V_1}{n_1}=\frac{V_2}{n_2}$).

Step2: Assign values

Let $V_1 = 5.00\ L$, $n_1=0.965\ mol$, and $n_2 = 1.80\ mol$. We need to find $V_2$.

Step3: Rearrange the formula to solve for $V_2$

$V_2=\frac{n_2V_1}{n_1}$.

Step4: Substitute values into the formula

$V_2=\frac{1.80\ mol\times5.00\ L}{0.965\ mol}$.
$V_2=\frac{9.00}{0.965}\ L\approx9.33\ L$.

Answer:

$9.33\ L$