Question

1. choose all that apply. identify the two cations in the following chemical equation: mg(s) + cu(no₃)₂(aq) → mg(no₃)₂(aq) + cu(s) options: cu²⁺, o²⁻, mg²⁺, n³⁻

Explanation:

Step1: Analyze first reaction's key product

The reaction $\ce{Na2S(aq) + 2HCl(aq) -> 2NaCl(aq) + H2S(g)}$ produces gas $\ce{H2S}$, which is evidence of chemical change.

Step2: Identify cations in second reaction

For $\ce{Mg(s) + Cu(NO3)2(aq) -> Mg(NO3)2(aq) + Cu(s)}$, the aqueous ionic compound $\ce{Mg(NO3)2}$ dissociates into $\ce{Mg^{2+}}$, and the reactant $\ce{Cu(NO3)2}$ has $\ce{Cu^{2+}}$ (free in solution before reaction).

Answer:

1. For the reaction $\ce{Na2S(aq) + 2HCl(aq) -> 2NaCl(aq) + H2S(g)}$:

gas

1. For the reaction $\ce{Mg(s) + Cu(NO3)2(aq) -> Mg(NO3)2(aq) + Cu(s)}$:

$\ce{Cu^{2+}}$, $\ce{Mg^{2+}}$