Question

1. use the equation you built in the previous problem.

calculate how many moles of $ce{na_{2}co_{3}}$ would be produced from 0.0777 mole $ce{nahco_{3}}$ according to reaction #4.
$ce{2nahco_{3} -> na_{2}co_{3} + co_{2} + h_{2}o}$
i need a hint
$\boldsymbol{ce{mol na_{2}co_{3}}}$
the answer to this question depends on your answers to previous questions.
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Explanation:

Step1: Identify mole ratio

From the balanced equation $2\text{NaHCO}_3
ightarrow \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O}$, the mole ratio of $\text{NaHCO}_3$ to $\text{Na}_2\text{CO}_3$ is $2:1$.

Step2: Calculate moles of $\text{Na}_2\text{CO}_3$

Moles of $\text{Na}_2\text{CO}_3 = \frac{\text{Moles of NaHCO}_3}{2}$
$\text{Moles of Na}_2\text{CO}_3 = \frac{0.0777}{2}$

Answer:

0.03885 mol