Question

1. if reaction #4 occurs, you calculated that 0.03885 moles $ce{na_{2}co_{3}}$ will be produced.

calculate how many grams $ce{na_{2}co_{3}}$ will be produced if this reaction #4 occurs when $ce{nahco_{3}}$ (baking soda) decomposes.
i need a hint
g
the answer to this question depends on your answers to previous questions.
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Explanation:

Step1: Find molar mass of $\text{Na}_2\text{CO}_3$

Molar mass of $\text{Na}_2\text{CO}_3 = (2\times23) + 12 + (3\times16) = 46 + 12 + 48 = 106\ \text{g/mol}$

Step2: Convert moles to mass

Mass = Moles $\times$ Molar Mass
$\text{Mass of }\text{Na}_2\text{CO}_3 = 0.03885\ \text{mol} \times 106\ \text{g/mol}$

Answer:

$4.1181$ g