Question

1. a rock dropped in a graduated cylinder raises the level of water from 20 ml to 35 ml. the rock has a mass of 45 g. what is the density of the rock?

Explanation:

Step1: Find the volume of the rock

The volume of the rock is equal to the volume of water it displaces. So $V = 35\mathrm{mL}-20\mathrm{mL}= 15\mathrm{mL}$. Since $1\mathrm{mL} = 1\mathrm{cm}^3$, the volume $V = 15\mathrm{cm}^3$.

Step2: Calculate the density

The density formula is $
ho=\frac{m}{V}$, where $m = 45\mathrm{g}$ and $V=15\mathrm{cm}^3$. Substitute the values into the formula: $
ho=\frac{45\mathrm{g}}{15\mathrm{cm}^3}=3\mathrm{g/cm}^3$.

Answer:

$3\mathrm{g/cm}^3$