Question

26 multiple choice 2 points rank the molecules below from most to least water soluble. a: h3c - c - h2 - oh b: h3c - c - h2 - ch3 c: h3c - cl d: h3c - c - h2 - c - h2 - c - h2 - ch3 a>c>b>d a>c>d>b a>b>c>d d>b>c>a

Explanation:

Step1: Analyze molecule A

A is an alcohol ($CH_3CH_2OH$). The -OH group can form hydrogen - bonds with water molecules, making it highly water - soluble.

Step2: Analyze molecule C

C is a chloro - alkane ($CH_3Cl$). It is polar due to the electronegativity difference between C and Cl. While it cannot form hydrogen bonds like an alcohol, its polarity allows some solubility in water.

Step3: Analyze molecule B

B is an alkane ($CH_3CH_3$). Alkanes are non - polar molecules. They have weak London dispersion forces and do not interact well with the polar water molecules, resulting in low solubility.

Step4: Analyze molecule D

D is a larger alkane ($CH_3CH_2CH_2CH_2CH_3$). Larger non - polar alkanes have even lower solubility in water compared to smaller alkanes because the non - polar part of the molecule dominates, and the interaction with water is minimal. So the order of water solubility from most to least is A>C>B>D.

Answer:

A. A>C>B>D