Question

1. the specific heat of aluminium is 0.900 j/g°c. how much energy is required to heat 15.0g of aluminium from 25.0°c to 90.0°c? (3pts)

heat = mass × specific heat × δt
where δt = t_final - t_initial
□ 877 j
□ 615 j
□ 194 j
□ 533 j

Explanation:

Step1: Calculate temperature change

$\Delta t = t_{final} - t_{initial} = 90.0^\circ\text{C} - 25.0^\circ\text{C} = 65.0^\circ\text{C}$

Step2: Plug values into heat formula

$\text{heat} = \text{mass} \times \text{specific heat} \times \Delta t = 15.0\ \text{g} \times 0.900\ \text{J/g}^\circ\text{C} \times 65.0^\circ\text{C}$

Step3: Compute the final heat value

$\text{heat} = 15.0 \times 0.900 \times 65.0 = 877.5\ \text{J} \approx 877\ \text{J}$

Answer:

$\boldsymbol{877\ \text{J}}$ (Option: $\boldsymbol{\square\ 877\ J}$)