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32) calculate the number of moles in 150.0 grams of calcium carbonate (…

Question

  1. calculate the number of moles in 150.0 grams of calcium carbonate (caco₃). a. 1.499 mol b. 1.006 mol c. 0.0000 mol d. 16.00 mol e. 1.565 mol 33) convert 255.0 grams to pounds (lb). a. 0.5622 lb b. 116.7 lb c. 662.2 lb d. 2550 lb e. 255,000 lb

Explanation:

Step1: Recall conversion factor

1 pound (lb) = 453.592 grams (g). So, to convert grams to pounds, we use the formula $m_{lb}=\frac{m_{g}}{453.592}$, where $m_{lb}$ is mass in pounds and $m_{g}$ is mass in grams.

Step2: Substitute given value

Given $m_{g} = 255.0$ g. Then $m_{lb}=\frac{255.0}{453.592}\approx0.5622$ lb.

Answer:

A. 0.5622 lb