Question

1. calculate the number of moles in 160.0 grams of calcium carbonate (caco3). a 1.499 mol b 1.056 mol c 0.6000 mol d 15.00 mol e 1.596 mol

Explanation:

Step1: Find molar - mass of CaCO₃

The molar - mass of Ca (calcium) is approximately 40.08 g/mol, C (carbon) is 12.01 g/mol, and O (oxygen) is 16.00 g/mol. For CaCO₃, the molar - mass \(M\) is \(M = 40.08+12.01 + 3\times16.00=40.08 + 12.01+48.00 = 100.09\) g/mol.

Step2: Calculate number of moles

The formula for the number of moles \(n\) is \(n=\frac{m}{M}\), where \(m\) is the mass and \(M\) is the molar - mass. Given \(m = 160.0\) g and \(M = 100.09\) g/mol, then \(n=\frac{160.0}{100.09}\approx1.598\) mol.

Answer:

E. 1.598 mol