Question

67.2 liters of nitrogen gas (n₂) at standard temperature and pressure (stp). how many moles of nitrogen gas are present? 3.0 mol 1.5 mol 6.0 mol 4.0 mol

Explanation:

Step1: Recall STP molar volume

At STP (standard temperature and pressure, 0°C and 1 atm), 1 mole of any ideal gas occupies 22.4 liters. So the molar volume \( V_m = 22.4 \, \text{L/mol} \).

Step2: Calculate moles using volume

The formula to find moles (\( n \)) from volume (\( V \)) and molar volume (\( V_m \)) is \( n=\frac{V}{V_m} \). Given \( V = 67.2 \, \text{L} \) and \( V_m = 22.4 \, \text{L/mol} \), substitute the values: \( n=\frac{67.2}{22.4} \).

Step3: Perform the division

\( \frac{67.2}{22.4}=3.0 \).

Answer:

3.0 mol