Question

arrange the following bonds in order of decreasing ionic character: mg - n, li - n, si - c. select the single best answer. o mg - n, li - n, si - c o mg - n, si - c, li - n o li - n, mg - n, si - c o li - n, si - c, mg - n o si - c, mg - n, li - n o si - c, li - n, mg - n

Explanation:

Step1: Recall electronegativity concept

Ionic character is determined by electronegativity difference.

Step2: Find electronegativity values

Electronegativity of Mg = 1.31, Li = 0.98, Si = 1.90, N = 3.04, C = 2.55.

Step3: Calculate electronegativity differences

For Mg - N: $\Delta\chi=3.04 - 1.31=1.73$.
For Li - N: $\Delta\chi=3.04 - 0.98 = 2.06$.
For Si - C: $\Delta\chi=2.55 - 1.90=0.65$.

Step4: Arrange by difference

Higher difference means higher ionic character. So order is Li - N, Mg - N, Si - C.

Answer:

Li - N, Mg - N, Si - C