Question

1. balance the chemical equation for the combustion reaction by typing the numbers in the blanks. butane (c₄h₁₀) and oxygen (o₂): c₄h₁₀ + o₂ → co₂ + h₂o 4) balance the chemical equation for the combustion reaction by typing the numbers in the blanks. benzene (c₆h₆) and oxygen (o₂): c₆h₆ o₂ → co₂ + h₂o 5) balance the chemical equation for the combustion reaction by typing the numbers in the blanks. ethyne (c₂h₂) and oxygen (o₂): c₂h₂ + o₂ → co₂ + h₂o

Explanation:

Step1: Balance butane combustion

Step1a: Balance C atoms

$1\text{C}_4\text{H}_{10} + \text{O}_2
ightarrow 4\text{CO}_2 + \text{H}_2\text{O}$

Step1b: Balance H atoms

$1\text{C}_4\text{H}_{10} + \text{O}_2
ightarrow 4\text{CO}_2 + 5\text{H}_2\text{O}$

Step1c: Balance O atoms

$1\text{C}_4\text{H}_{10} + \frac{13}{2}\text{O}_2
ightarrow 4\text{CO}_2 + 5\text{H}_2\text{O}$

Step1d: Eliminate fraction

$2\text{C}_4\text{H}_{10} + 13\text{O}_2
ightarrow 8\text{CO}_2 + 10\text{H}_2\text{O}$

Step2: Balance benzene combustion

Step2a: Balance C atoms

$1\text{C}_6\text{H}_6 + \text{O}_2
ightarrow 6\text{CO}_2 + \text{H}_2\text{O}$

Step2b: Balance H atoms

$1\text{C}_6\text{H}_6 + \text{O}_2
ightarrow 6\text{CO}_2 + 3\text{H}_2\text{O}$

Step2c: Balance O atoms

$1\text{C}_6\text{H}_6 + \frac{15}{2}\text{O}_2
ightarrow 6\text{CO}_2 + 3\text{H}_2\text{O}$

Step2d: Eliminate fraction

$2\text{C}_6\text{H}_6 + 15\text{O}_2
ightarrow 12\text{CO}_2 + 6\text{H}_2\text{O}$

Step3: Balance ethyne combustion

Step3a: Balance C atoms

$1\text{C}_2\text{H}_2 + \text{O}_2
ightarrow 2\text{CO}_2 + \text{H}_2\text{O}$

Step3b: Balance H atoms

$1\text{C}_2\text{H}_2 + \text{O}_2
ightarrow 2\text{CO}_2 + 1\text{H}_2\text{O}$

Step3c: Balance O atoms

$1\text{C}_2\text{H}_2 + \frac{5}{2}\text{O}_2
ightarrow 2\text{CO}_2 + 1\text{H}_2\text{O}$

Step3d: Eliminate fraction

$2\text{C}_2\text{H}_2 + 5\text{O}_2
ightarrow 4\text{CO}_2 + 2\text{H}_2\text{O}$

Answer:

1. $2\text{C}_4\text{H}_{10} + 13\text{O}_2

ightarrow 8\text{CO}_2 + 10\text{H}_2\text{O}$

1. $2\text{C}_6\text{H}_6 + 15\text{O}_2

ightarrow 12\text{CO}_2 + 6\text{H}_2\text{O}$

1. $2\text{C}_2\text{H}_2 + 5\text{O}_2

ightarrow 4\text{CO}_2 + 2\text{H}_2\text{O}$