Question

balance the following acid - base reaction.

• use the simplest possible whole numbers, and make sure to enter a 1 if one of the given compound is needed.

provide your answer below:
$h_2so_4 + 2lioh longrightarrow square h_2o+square li_2so_4$

Explanation:

Step1: Balance Li atoms

On the left - hand side, there are 2 Li atoms in $2LiOH$. On the right - hand side, in $Li_2SO_4$, we put a coefficient of 1 for $Li_2SO_4$ to balance Li atoms.

Step2: Balance H and O atoms

In $H_2SO_4$ and $2LiOH$, there are a total of 4 H atoms and 6 O atoms on the left - hand side. In $Li_2SO_4$, there are 4 O atoms. So, we put a coefficient of 2 for $H_2O$ to balance H and O atoms. So the balanced equation is $H_2SO_4 + 2LiOH \longrightarrow 2H_2O + Li_2SO_4$.

Answer:

$H_2SO_4 + 2LiOH \longrightarrow 2H_2O+1Li_2SO_4$