Question

this balanced chemical equation demonstrates the law of conservation of mass, meaning the number of each type of atom is equal on both sides of the equation. match each element with the number of atoms found in the reactants and products. c (carbon) o (oxygen) h (hydrogen)

Explanation:

Step1: Count carbon atoms

On the reactant side, in $6CO_2$, the number of carbon atoms is $6\times1 = 6$. On the product side, in $C_6H_{12}O_6$, the number of carbon atoms is 6.

Step2: Count oxygen atoms

On the reactant side, in $6CO_2$ there are $6\times2=12$ oxygen atoms and in $6H_2O$ there are $6\times1 = 6$ oxygen atoms, so in total $12 + 6=18$ oxygen atoms. On the product side, in $C_6H_{12}O_6$ there are 6 oxygen atoms and in $6O_2$ there are $6\times2 = 12$ oxygen atoms, so in total $6+12 = 18$ oxygen atoms.

Step3: Count hydrogen atoms

On the reactant side, in $6H_2O$, the number of hydrogen atoms is $6\times2=12$. On the product side, in $C_6H_{12}O_6$, the number of hydrogen atoms is 12.

Answer:

C (carbon) - 6, O (oxygen) - 18, H (hydrogen) - 12