Question

this balanced chemical equation demonstrates the law of conservation of mass, meaning the number of each type of atom is equal on both sides of the equation. 6co₂ + 6h₂o → c₆h₁₂o₆ + 6o₂. match each element with the number of atoms found in the reactants and products. c (carbon) o (oxygen) h (hydrogen)

Explanation:

Step1: Count carbon atoms

In reactants: $6$ in $6CO_2$. In products: $6$ in $C_6H_{12}O_6$. So, 6 carbon atoms.

Step2: Count oxygen atoms

In reactants: $6\times2$ (from $6CO_2$) + $6$ (from $6H_2O$) = $12 + 6=18$. In products: $6$ (from $C_6H_{12}O_6$) + $6\times2$ (from $6O_2$) = $6+12 = 18$. So, 18 oxygen atoms.

Step3: Count hydrogen atoms

In reactants: $6\times2$ (from $6H_2O$) = 12. In products: $12$ (from $C_6H_{12}O_6$). So, 12 hydrogen atoms.

Answer:

C (carbon): 6
O (oxygen): 18
H (hydrogen): 12