Question

ca(oh)₂ + co₂ → caco₃ + h₂o. this balanced chemical equation demonstrates the law of conservation of mass, meaning the number of each type of atom is equal on both sides of the equation. match each element with the number of atoms found in the reactants and products. some numbers may not be used. c (carbon) o (oxygen) h (hydrogen) ca (calcium)

Explanation:

Step1: Analyze carbon atoms

In the reactant $\text{CO}_2$, there is 1 carbon atom and in the product $\text{CaCO}_3$, there is 1 carbon atom. So, the number of carbon atoms is 1.

Step2: Analyze oxygen atoms

In $\text{Ca(OH)}_2$ there are 2 oxygen atoms, in $\text{CO}_2$ there are 2 oxygen atoms. In the products, in $\text{CaCO}_3$ there are 3 oxygen atoms and in $\text{H}_2\text{O}$ there is 1 oxygen atom, for a total of 4 oxygen atoms in the reactants and 4 oxygen atoms in the products.

Step3: Analyze hydrogen atoms

In $\text{Ca(OH)}_2$ there are 2 hydrogen atoms, and in $\text{H}_2\text{O}$ there are 2 hydrogen atoms. So, the number of hydrogen atoms is 2.

Step4: Analyze calcium atoms

In $\text{Ca(OH)}_2$ there is 1 calcium atom and in $\text{CaCO}_3$ there is 1 calcium atom. So, the number of calcium atoms is 1.

Answer:

C (Carbon): 1
O (Oxygen): 4
H (Hydrogen): 2
Ca (Calcium): 1