Question

a chemist determined by measurements that 0.0150 moles of silver participated in a chemical reaction. calculate the mass of silver that participated in the chemical reaction. be sure your answer has the correct number of significant digits.

Explanation:

Step1: Recall molar - mass formula

The formula to calculate mass ($m$) from moles ($n$) and molar mass ($M$) is $m = n\times M$. The molar mass of silver ($Ag$) is $M = 107.87\ g/mol$.

Step2: Substitute values

We are given $n = 0.0150\ mol$ and $M=107.87\ g/mol$. Substitute these values into the formula: $m=0.0150\ mol\times107.87\ g/mol$.

Step3: Calculate the mass

$m = 0.0150\times107.87=1.61805\ g$.

Step4: Round to significant digits

The number of moles ($0.0150$) has 3 significant digits. So, rounding $1.61805\ g$ to 3 significant digits gives $m = 1.62\ g$.

Answer:

$1.62\ g$